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  Loading ... |  Click here to read | Other diodes have been waiting long enough to be placed inside the two layer shield to rest. So I finally took the entire IR Photodiode setup apart, which required handling of everything. Unfortunately, it’s a safe bet that the IR Photodiode is now disturbed. Lets hope the free energy movement will begin to learn real science. Lets please end the guessing games, and blindly replicating. You probably won’t learn enough in say 1/2 year to become a paid physicists, but you could easily learn enough to conduct free energy research in a specific field such as Cold Fusion or Diode research. Self-education: Real scientists: Online degree: Scientific method: Last night the IR Photodiode was measured at producing 10.9 pA DC. Well, it appears the photodiode is not done yet. At this point it’s there’s still insufficient data to tell if the diode was suddenly disturbed, or if it merely dropped to its preferred DC current level of ~ 10 pA, or if it’s now in the stage of recovering from whatever disturbed it to perhaps rise back up to the ~ 20 pA level. One very interesting observation in the IR Photodiode data over the past week is that it appears to have *jumped* from ~ 20 pA range down to the ~ 10 pA range. The photodiode was producing over 20 pA, and then suddenly jumped down to half that value, as if there are energy bands. I noticed this same behavior in my SMS7630 diode, where there appeared (still inconclusive) that the diode array had preferred voltage levels. It was as if the SMS7630 diodes would jump to the next voltage level. So, will the IR Photodiode jump back up to the next level? Will it gradually rise the entire way up? Or will it gradually decrease over time? It would be nice to get an answer soon because I have several other diodes that I would like to place inside the double layer metal shield. Tonight the IR photodiode was measured at producing 7.3 pA. The DC current steadily going down. If it goes below zero pA into a negative current then it means the photodiode is disturbed. I know from the previous long term experiment that this same photodiode without the load and just the capacitor slowly faded from ~ 10 mV down to ~ 1/2 mV in a matter of a month. Will the loaded/capacitor photodiode do the same thing, or is it just disturbed. After we see what the photodiode is going to do, the next long term experiment will be to see how the photodiode does with a load without the 1uF capacitor. It’s well know by conventional physics that capacitance removes a significant amount of ambient thermal noise from the resistor. Perhaps this is partially starving the photodiode. What’s even more surprising is that you can’t judge an LED by it’s color. White LED’s are merely blue LED’s with a coating that converts the blue light into white. For example, consider the following two *white* LED’s –> LED part #: LXHL-BW02 LED part #: NSCW100 As you can see, the produced voltage difference between these white LED’s is nearly 10000 times, yet they are both white LED’s. Could this be the reason why I’m having such difficulty in getting my white LED’s to produce? Or are they still disturbed after a few weeks of resting inside a heavily metal shielded dark container? The near zero bias resistance should be measured with 10 pA of DC current flowing through the diode. You would take a resistor of preferably no less than 50 Mohm placed in series with the LED and in series with a variable voltage source. If you only have 10 Mohm resistors, then place at least 5 in series. You would then measure the DC voltage across the resistor. Since your voltage meter is probably not in the giga ohms input resistance, you’ll want to place a good capacitor of at least 5uF across the 50 Mohm resistor. Also, place another 5uF capacitor across the LED. Do not place the voltage meter directly across the 50 Mohm resistor. Turn on the voltage source at a low voltage. Give the capacitor time to charge according to the RC time constant. If it’s 5uF across a 50 Mohm load, then in 19.2 minutes the capacitor will be charged to 99%. Then quickly place your voltage meter across the capacitor to measure the voltage. If you voltage meter is significantly less than 100 Mohm input resistance, then you may have some difficulties measure the voltage on a 5uF cap, as the meter will quickly drain the capacitor. If the resistor is 50 Mohm, then you want to measure 0.5 mV across the resistor & capacitor. If it’s less than 0.5 mV, then slightly increase the voltage source. Remember, the LED resistance is non-linear. After you get 10 pA of DC current flowing through the diode, next you will want to measure the DC voltage across the LED (and it’s capacitor) while there’s 10 pA of current. The LED should also have a capacitor across it. Again, the reason for the capacitor is so you can quickly obtain a proper DC voltage measurement across the LED. Now that you have the current and voltage, you simply divide the voltage by current to obtain Rz. For example, if the voltage across the diode was 5 mV, then Rz is 5 mV / 10 pA = 500 Mohm. It would best to not disturb the diode, otherwise the Rz measurement might be off a bit, but that might be a difficult task. Any measurement is better than none. The recent LED surprise –> http://globalfreeenergy.info/2009/05/25/led-surprise/ should be very helpful. The LED runt, NSCW100, that only produces 0.147 mV could be used as a light source that a LED array would light up. IOW, you have a LED array made of high DC voltage producing LED’s, such as the LXHL-BW02, and that LED array output would be connected to the runt NSCW100 LED since the NSCW100 does not produce much DC voltage. Or at least that’s the theory. … Hm, I can already think of reasons why the runt could counter act the LED array. It would well be worth the try. What a surprise! I was wondering just how much the near zero bias resistance of various LED’s varied. So I tried some of the LED’s in LTspice database. What a surprise at how low the near zero bias resistance is on some LED’s! For example, the NSCW100 was only 14.7 Mohms!!! The predicted DC voltage produced by this diode while undisturbed is only 0.147 mV. Here’s data on some LED’s –> Predicted DC voltages produced by LED’s, in order of lowest Rz: LED part #: NSCW100 LED part #: AOT-2015 LED part #: NSPW500BS LED part #: NSSW008CT-P1 LED part #: QTLP690C LED part #: LXK2-PW14 LED part #: NSSWS108T LED part #: LXHL-BW02 Last night the IR Photodiode measured at producing 9.3 pA. This sudden drop could be from the fact that I had to move the entire setup to get access to some bins, or it from an external source. Perhaps there was a sudden EM pulse, a gamma ray, etc. It’s difficult to say. It will be interested to see what happens next. Maybe the moving around of the diode setup disturb it. Do heavy vibrations also disturb sensitive diodes? I doubt it. If we had diode researchers around the world testing diodes, then we could tell if such a disturbance was on a global scale, perhaps from a Coronal mass ejection, or a Supernova, or some Gamma-ray bursts (GRBs). Anyone, please let me know if there was any such known occurrence between May 22nd and 24th. Consider my present experiment of an IR photodiode that’s been inside two layers of metal shielding for several months in a dark room. I don’t have my logs in front of me, but for ~~ a month now it’s been connected across a 193Mohm load and simultaneously across a 1uF low leakage capacitor. The IR photodiode has been producing close to 20 pA the entire time. Dielectric absorption is a momentary effect that occurs after the capacitor’s charge has varied, and the effect fades in time relatively fast. The diode effect that I refer to as the TED (thermal equilibrium diode), has the opposite effect where the DC current/voltage produced by the diode is lowest after being disturbed (soldering, induced voltage from external source, sudden temperature change, etc.), and slowly increasing over time as the diode settles down. I’ve conducted diode experiments in countless rural locations from inside caves, to within ~ 5 to 7 story high canyons, to on the beach behind a ~ 10 story high cliff, to out in open areas in desert, and also forest locations, all within either two or three layers of metal shielding (small, medium, and large metal shield). Also my SMS7630 diode array has been tested while buried two feet in the ground. Furthermore, the SMS7630 diodes were tested in an oil bath. The diodes have always produced a DC voltage. I’ve tested low leakage capacitors. Dielectric absorption is a simple effect to analyze. The DC currents and voltages that I am seeing are not caused by dielectric absorption. As far as I know, the final remaining conventional theory to explain the voltage/current produced by diodes is electrochemical reactions within the diode, but this theory was put to rest a few weeks ago when diodes repeatedly failed to retain a charge from a charging current. If anything, the charging current disturbs the diodes ability to produce a DC current/voltage– TED effect. My years of testing various types of batteries, especially dead batteries, has shown that all batteries (rechargeable and so-called non-rechargeable) accept an appreciable charge from a charging current. Diodes, or at least my diodes, do not charge from a charging current. Various amounts of applied voltages from millivolts to 32 volts was applied to the diodes. The diodes did not accept any charge from the charging current. Furthermore, the best semiconductor mathematics based on quantum physics clearly predicts that the diode must rectify ambient thermal noise. The so-called genius, Mike Engelhardt, creator of LTspice, admits this is correct. The 2nd Law of Thermodynamics is macro system of averages. At a microscopic scale one atom could be moving at 5000 m/s while it’s neighbor at a near standstill. For any isolated system with a mass of a few picograms (45,000,000,000 Aluminum atoms weighs 2 picograms), probability of observing an increase in entropy is measurable– reference: Landau, L.D.; Lifshitz, E.M. (1996). Statistical Physics Part 1. Butterworth Heinemann. ISBN 0-7506-3372-7. More academic scientists than ever are now consider the real possibility that the 2nd Law of Thermodynamics is a tendency, not a law. The amount of ambient thermal energy contained within solids on Earth is ~ 1 billion joules, which is sustained by the Sun. That’s only considering ambient thermal energy, not mass-energy. The amount of mass-energy in 1 m^3 of iron, E=mc^2, is 7.1E+20 joules. The concept that it is *impossible* to capture such energy as usable energy is unintuitive, goes against the best present conventional semiconductor mathematics, and is not supported by 1.5 years of well thought out and careful diode measurements. For anyone who’s interested in conducting such diode research, please contact me. I *CANNOT* stress enough the importance of taking extreme precautions in not disturbing the diode, in allowing the diode sufficient time inside metal shielding in the dark (if the diode casing is transparent). One just cannot stick a diode on a meter and expect it to behave like an Alkaline battery. I wish that were the case. The diodes are easily disturbed– TED effect. Even the act of taking too many measurements at a given time is a sure method of disturbing the diodes. A diode changing from undisturbed to slightly disturbed will cause the produced DC voltage/current to slowly begin to drop, which could take the diode days to weeks to slowly drop to a low point. A diode changing from undisturbed to highly disturbed could change in a matter of seconds. Trying to understand the TED effect is the present goal. The present theory to explain the TED effect is by means of the Thermoelectric effects. Despite the fact that Tom Schum has *not* taken my ongoing advice, he’s managed to get some good results from disturbed green LED’s. He’s testing four LED’s, all enclosed inside a tight metal shielded container. The measurements so far are 3.3mV, 1.9mV, 1.0mV, 1.9mV. If Tom will take my advice, and let these poor LED’s recover, he’ll see some amazing results. Not that the above isn’t amazing, because 3.3mV is, but if Tom Schum keeps it up, and starts to listen to me, he’ll have no trouble obtaining hundreds of millivolts. I’ve been doing diode measurements since late 2007. I’ve taken every precaution. My green LED charged a 1uF low leakage capacitor to 353mV (0.353 volts) in 10 hours. The predicted voltage from 10 hours of charging was 360mV. The present tests are on a different diode, an IR photodiode, that is producing over 20 pA of DC current. If you’re an animal lover like me, then you probably adore the Discovery reality TV series on the Animal Planet, “Escape to Chimp Eden.” It’s normally on Friday nights, but they did an unannounced time change to Thursday nights, which meant a lot of people missed it Thursday! If you could take a few minutes, could you please write the Discovery channel a quick note using their online contact page –> http://extweb.discovery.com/viewerrelations Here’s the letter I wrote –> +++ Dear Discovery, You changed the air time of Escape to Chimp Eden without notice! Could you ***PLEASE*** replay it. That is my favorite show of all time ever, and I was heart broken to not see it Friday night. It turns out that it was played the night before, Thursday. Could you please replay the 2009/5/21 Escape to Chimp Eden again?? Love you network! Thanks so much! +++ You could modify my text to your own words. Thanks everyone! Just moments ago the IR photodiode was measured at producing 20.7 pA DC. This is great news because it appears the IR photodiode is not decaying to zero amps, as it’s staying around 20pA. Prior that I tested the white LED that’s been resting while connected to a 45 Mohm load and 4.7uF cap. It’s been resting for, what, ~ a week, and it was measured at 0.0mV with the AM-240, which only means it was producing less than 0.1mV. Actually I can tell that it was definitely over 0.0mV because the polarity sign on the AM-240 will toggle back and forth between 0.0mV and -0.0mV. In fact, just after testing the white LED today I took the AM-240 meter and connected it to a 30 Mohm resistor (nothing else, just a resistor), and the polarity sign toggled nicely back and forth showing that there was zero volts across the 30 Mohm resistor. Then I reverse the AM-240 probes, which showed the same results, the polarity sign switching back and forth; i.e., 0.0mV and -0.0mV. Does this mean that disturbed visible light LED’s take a long time to recover? That’s a great question. This is interesting –> http://www.youtube.com/watch?v=mzX3gdZIaak http://www.youtube.com/watch?v=rSU8_K4TAO4 Just when the IR photodiode was showing a predictable sign, it changes again. Another possibility is that the IR photodiode is merely adjusting to the change in load, and perhaps will settle down around 10 pA. Another possibility is that the IR photodiode’s DC current will continue to slowly decade so long as it’s connected to a capacitor. Tonight the IR Photodiode was measured at producing 17.1 pA DC. Everyone needs to stop the drunk wobbly guessing scientific methodology. What we have is by no means a free energy movement. On 2009, May 03 I divorced myself from what might be referred to as the free energy community, and I hope all legit researchers do the same! Please consider. Educate yourself– see my recent blog on self-education. You don’t need to spend half of your time on the forums chit chatting. Nobody needs to know what you’re doing until you succeed! That is how we are going succeed in achieving global free energy. Not by guessing at “Oh, what will happen if I place a magnet here, or there because my Intuition says so.” Take a look at all the work done in the free energy movement. All of it’s a bunch of people replicating claims. So we have the fakers creating junk, and the kids replicating them. That’s *no* free energy movement! That’s a bunch of junk that’s a guaranteed recipe to failure. It’s not science. The Scientific method is about trying to understand and discover something by means of a scientific logical method. For example, if someone thought of an integer betwen 0 and 10000, and asked you to guess, which method would you prefer –> Method #1 – the guesser: Method #2 – process of elimination: If you think there’s an unknown magnetic anomaly, then by all means test it, but for heaven sake don’t wobble around placing random parts here and there hoping to discover the holly grail. If for instance you think two magnets moving perpendicular to each other will produce an unknown effect, then test it in a scientific manner. You don’t need a degree from a University! Design a setup, map out the forces, and stop the wobbly guessing games. If you stumble upon a problem on how to achieve or calculate something, then just post your question in one of the countless science forums. That’s how you’ll learn. You’ll also learn by reading science textbooks. Spend at least 30 minutes per day reading them. See one of my recent blog posts on self-education. There you will learn where to buy University textbooks from a few dollars or less each.
If you keep that up for a few years, you could qualify as an Honorary scientist. If you so desire, it could be your new career to bring home the bacon, a career you’ll probably love. There are countless companies that do not require a college degree. And who knows, may you’ll be the one to discover the holly grail, or at least make some major breakthroughs. We need your help. We don’t need the wobbly drunken scientists! Last night the IR photodiode was measured producing 19.2 pA DC. BTW, the resolution is 0.518 pA. Although if the meters reading flips back and forth between digits, then on occasion I will write that down as 1/2 digit, which would provide 0.259 pA resolution. The measurements are not accurate to 0.1 pA, but I merely provide the answers down to .2 pA for convenience. Although it’s still not entirely convincing, it does appear the IR photodiode is stabilizing near 20 pA DC. | ||||
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Just how disturbed remains to be seen in a few days for the next IR Photodiode measurement.
Last night it was producing 15 pA. Once again I’ll wait two days for the next measurement because with past diode (arrays) the DC voltage/current would always begin to take a dive when I took daily measurements.