Global Free Energy Blog

“We have two ears and one mouth so that we can listen twice as much as we speak.”

by Epictetus

Other diodes have been waiting long enough to be placed inside the two layer shield to rest. So I finally took the entire IR Photodiode setup apart, which required handling of everything. Unfortunately, it’s a safe bet that the IR Photodiode is now disturbed. Just how disturbed remains to be seen in a few days for the next IR Photodiode measurement.

Lets hope the free energy movement will begin to learn real science. Lets please end the guessing games, and blindly replicating. You probably won’t learn enough in say 1/2 year to become a paid physicists, but you could easily learn enough to conduct free energy research in a specific field such as Cold Fusion or Diode research.

Self-education:
http://globalfreeenergy.info/2009/05/18/self-education/

Real scientists:
http://globalfreeenergy.info/2009/05/18/real-scientists/

Online degree:
http://en.wikipedia.org/wiki/Online_degree

Scientific method:
http://en.wikipedia.org/wiki/Scientific_method

Last night the IR Photodiode was measured at producing 10.9 pA DC. Well, it appears the photodiode is not done yet. At this point it’s there’s still insufficient data to tell if the diode was suddenly disturbed, or if it merely dropped to its preferred DC current level of ~ 10 pA, or if it’s now in the stage of recovering from whatever disturbed it to perhaps rise back up to the ~ 20 pA level.

One very interesting observation in the IR Photodiode data over the past week is that it appears to have *jumped* from ~ 20 pA range down to the ~ 10 pA range. The photodiode was producing over 20 pA, and then suddenly jumped down to half that value, as if there are energy bands. I noticed this same behavior in my SMS7630 diode, where there appeared (still inconclusive) that the diode array had preferred voltage levels. It was as if the SMS7630 diodes would jump to the next voltage level.

So, will the IR Photodiode jump back up to the next level? Will it gradually rise the entire way up? Or will it gradually decrease over time? It would be nice to get an answer soon because I have several other diodes that I would like to place inside the double layer metal shield.

Tonight the IR photodiode was measured at producing 7.3 pA. The DC current steadily going down. If it goes below zero pA into a negative current then it means the photodiode is disturbed. I know from the previous long term experiment that this same photodiode without the load and just the capacitor slowly faded from ~ 10 mV down to ~ 1/2 mV in a matter of a month. Will the loaded/capacitor photodiode do the same thing, or is it just disturbed.

After we see what the photodiode is going to do, the next long term experiment will be to see how the photodiode does with a load without the 1uF capacitor. It’s well know by conventional physics that capacitance removes a significant amount of ambient thermal noise from the resistor. Perhaps this is partially starving the photodiode.

What’s even more surprising is that you can’t judge an LED by it’s color. White LED’s are merely blue LED’s with a coating that converts the blue light into white. For example, consider the following two *white* LED’s –>

LED part #: LXHL-BW02
Emitted light color: White
Predicted voltage: 1240 mV

LED part #: NSCW100
Emitted light color: White
Predicted voltage: 0.147 mV

As you can see, the produced voltage difference between these white LED’s is nearly 10000 times, yet they are both white LED’s.

Could this be the reason why I’m having such difficulty in getting my white LED’s to produce? Or are they still disturbed after a few weeks of resting inside a heavily metal shielded dark container?

The near zero bias resistance should be measured with 10 pA of DC current flowing through the diode. You would take a resistor of preferably no less than 50 Mohm placed in series with the LED and in series with a variable voltage source. If you only have 10 Mohm resistors, then place at least 5 in series. You would then measure the DC voltage across the resistor. Since your voltage meter is probably not in the giga ohms input resistance, you’ll want to place a good capacitor of at least 5uF across the 50 Mohm resistor. Also, place another 5uF capacitor across the LED. Do not place the voltage meter directly across the 50 Mohm resistor. Turn on the voltage source at a low voltage. Give the capacitor time to charge according to the RC time constant. If it’s 5uF across a 50 Mohm load, then in 19.2 minutes the capacitor will be charged to 99%. Then quickly place your voltage meter across the capacitor to measure the voltage. If you voltage meter is significantly less than 100 Mohm input resistance, then you may have some difficulties measure the voltage on a 5uF cap, as the meter will quickly drain the capacitor. If the resistor is 50 Mohm, then you want to measure 0.5 mV across the resistor & capacitor. If it’s less than 0.5 mV, then slightly increase the voltage source. Remember, the LED resistance is non-linear.

After you get 10 pA of DC current flowing through the diode, next you will want to measure the DC voltage across the LED (and it’s capacitor) while there’s 10 pA of current. The LED should also have a capacitor across it. Again, the reason for the capacitor is so you can quickly obtain a proper DC voltage measurement across the LED.

Now that you have the current and voltage, you simply divide the voltage by current to obtain Rz. For example, if the voltage across the diode was 5 mV, then Rz is 5 mV / 10 pA = 500 Mohm.

It would best to not disturb the diode, otherwise the Rz measurement might be off a bit, but that might be a difficult task. Any measurement is better than none.

The recent LED surprise –>

http://globalfreeenergy.info/2009/05/25/led-surprise/

should be very helpful. The LED runt, NSCW100, that only produces 0.147 mV could be used as a light source that a LED array would light up. IOW, you have a LED array made of high DC voltage producing LED’s, such as the LXHL-BW02, and that LED array output would be connected to the runt NSCW100 LED since the NSCW100 does not produce much DC voltage. Or at least that’s the theory. … Hm, I can already think of reasons why the runt could counter act the LED array. It would well be worth the try.

What a surprise! I was wondering just how much the near zero bias resistance of various LED’s varied. So I tried some of the LED’s in LTspice database. What a surprise at how low the near zero bias resistance is on some LED’s! For example, the NSCW100 was only 14.7 Mohms!!! The predicted DC voltage produced by this diode while undisturbed is only 0.147 mV. Here’s data on some LED’s –>

Predicted DC voltages produced by LED’s, in order of lowest Rz:

LED part #: NSCW100
Rz: 14.7 Mohm
Predicted DC voltage: 0.147 mV

LED part #: AOT-2015
Rz: 268 Mohms
Predicted DC voltage: 2.68 mV

LED part #: NSPW500BS
Rz: 638 Mohm
Predicted DC voltage: 6.38 mV

LED part #: NSSW008CT-P1
Rz: 93.9 Gohm
Predicted DC voltage: 939 mV

LED part #: QTLP690C
Rz: 97.9 Gohm
Predicted DC voltage: 979 mV

LED part #: LXK2-PW14
Rz: LXK2-PW14
Predicted DC voltage: 1.01 volts

LED part #: NSSWS108T
Rz: 124 Gohm
Predicted DC voltage: 1.24 volts

LED part #: LXHL-BW02
Rz: 128 Gohm
Predicted DC voltage: 1.28 volts

Last night the IR Photodiode measured at producing 9.3 pA. This sudden drop could be from the fact that I had to move the entire setup to get access to some bins, or it from an external source. Perhaps there was a sudden EM pulse, a gamma ray, etc. It’s difficult to say. It will be interested to see what happens next.

Maybe the moving around of the diode setup disturb it. Do heavy vibrations also disturb sensitive diodes? I doubt it. If we had diode researchers around the world testing diodes, then we could tell if such a disturbance was on a global scale, perhaps from a Coronal mass ejection, or a Supernova, or some Gamma-ray bursts (GRBs). Anyone, please let me know if there was any such known occurrence between May 22nd and 24th.