Global Free Energy Blog

It just occurred to me that isolating the diodes or piezos from AC electrical noise (Johnson noise) is probably not going to work in terms of getting past the 10pA level. The parallel capacitance of my piezo is ~ 30nF. And the resistance of this piezo at such low current levels is in the giga ohm region. Therefore, the parallel capacitance is sufficient to short Johnson noise down to at least 0.01 Hz! So it does not seem to be related to AC electrical noise.

Obviously two piezos that are not connected to each other will *each* produce 10pA. IOW, they will not effect each other. So if it’s only due to electrical isolation, then it must be DC current isolation. Hmm, actually that’s easy to test! Just place a low leakage capacitor between (not across) each element. This will block DC current between each element. This is actually based on an old theory of mine, where the DC voltage fluctuates between elements over time, and this alone might disturb each other to some degree and prevent the net current from going beyond 10pA DC. I don’t know, it’s an old theory that I no longer care for. Anyhow, if it’s true that each element needs to be electrically DC isolated, then it will be unfortunate, as it could be difficult to isolate each component DC wise and still collect the 10pA from all parts.

So this is tested by placing a low leakage capacitor between each element. Of course you can’t get more than 10pA in totality, but each element hopefully will still produce it’s 10pA of current. If it does not, then it’s not AC or DC electrical current. If that turns out to be the case, then what is it? I mean, surely they can still be in the same room and each produce 10pA.

This morning the homemade was producing 9.7 pA.

This is such an exciting moment for me!!! Maybe I should wait another day to be certain before celebrating, but it’s looking great so far. Would you believe I’m celebrating over 10pA? That is correct, a few minutes ago the homemade diode was producing 10pA DC current!!!

This is so important for the research. It means we do not need any fancy or expensive diodes, piezos, electrets, etc. It means *all* undisturbed matter produces ~ 10pA of DC current so long as the net circuit resistance is low enough. For example, if the resistance of the junction (contact between dissimilar materials) is say 10 ohms, and you want to measure this 10pA of current, then the resistance of the rest of the circuit (e.g., your meter or a shunt resistor) must be appreciable less than 10 ohms. That’s why it’s extremely difficult to see this current in ordinary matter. To see this effect it’s best to use an insulator.

Lets say we take three fine powders and mix them together. One of powders act as insulator; e.g., quartz. The other two are the dissimilar elements. Bond the particles together with heat. Once cooled down and allowed to recover, within the mixture exists microscopic current loops of ~ 10pA.

So how do you get the currents to align. That is simple. While the materials are heated up to the proper temperature, an intense electric field is applied. If the field is intense enough, and the temperature is correct, the electric junctions (dissimilar materials) will physically align given enough time This is an exact description of the Crystal batteries made by Marcus Reid & John Hutchison.

Once the homemade diode is finally confirmed as producing a stabilized 10pA DC current, the final goal is to find a material that will properly isolate the microscopic electric junctions while still allow for DC current.

Good news so far. … knock on wood!

About 1 or 2 hours ago the measured current was 7.9pA DC.

A few minutes ago the measured current was 9.0pA DC.

The current obviously bounced and ~ 2 years of diode testing experience tells me that it’s trying to maintain the 10pA. Lets hope this homemade diode has what it takes to succeed. The diodes experiments showed that the current would often stay around 10pA, and then suddenly jump to a lower level such as 5pA or 2.5pA due to being measured to often. When the measurements were cut back, then the current would eventually go back up to 10pA.

Wow, the homemade diode current has made a sudden drop to 21pA! Just this morning, about 4.5 hours ago it was 79pA. This sudden rapid drop in current has me a bit concerned because at this rate it will go below 10pA. Although, I have seen a lot of diode experiments where the current will drop in jumps, as if there are energy levels.

Another option is the homemade diode was disturbed, and is in the common slow decay state, in which case it will go below 10pA, but given enough time will recover.

Another option is the homemade diode is to poorly made, and perhaps the built in electric field is too weak, and therefore is insufficient to sustain the 10pA DC current.